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4x^2-180x+800=0
a = 4; b = -180; c = +800;
Δ = b2-4ac
Δ = -1802-4·4·800
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{19600}=140$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-140}{2*4}=\frac{40}{8} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+140}{2*4}=\frac{320}{8} =40 $
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